$In a mixture, there is 200 litres of milk and 40 litres of water. (x) litres of mixture is drawn and (y) litres of pure water is added, the milk in the mixture is 124 litres more than the water.$ A. 36, 12 B. 24, 8 C. 18, 20 D. 12, 6

Initial mixture: milk = 200L, water = 40L. Total = 240L with milk ratio = 200/240 = 5/6. After drawing x litres and adding y litres water: remaining milk = 200 - (5/6)x, total water = 40 - (1/6)x + y. Given milk = water + 124. So 200 - (5/6)x = 40 - (1/6)x + y + 124 = 164 - (1/6)x + y. Simplifying: 36 - (5/6)x = -(1/6)x + y, so 36 - (4/6)x = y, or y = 36 - (2/3)x. For option A (x=36, y=12): 12 = 36 - (2/3)(36) = 36 - 24 = 12. This works. Final milk = 200 - 30 = 170, water = 40 - 6 + 12 = 46. Milk exceeds water by 124. Correct.