Multiple choice

A five letter word is formed using the letters P, R, I, M and E (repetition is not allowed). Find the probability of getting a word in which the consonants should not be together?

  1. $3/5$
  2. $2/5$
  3. $7/10$
  4. $4/5$
  5. $3/10$
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Total 5-letter words from PRIME = 5! = 120. Consonants (P,R,M) should not be together. First find arrangements with consonants together: treat PRM as one unit - 3! × 3! = 36. Words with consonants NOT together = 120 - 36 = 84. Probability = 84/120 = 7/10.