Multiple choice

Q is 1.5 time efficient than P. If P can do 6/7 part of a certain work in 12 days. If Q worked for 6 days, then what part of the work will remain incomplete?

  1. 3/5

  2. 6/7

  3. 1/11

  4. 5/14

Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

P's work rate = (6/7)/12 = 1/14 per day. Q is 1.5 times efficient, so Q's rate = 3/28 per day. In 6 days, Q completes 6 × 3/28 = 18/28 = 9/14 of the work. Remaining work = 1 - 9/14 = 5/14. The key is understanding that efficiency directly affects work rate, and Q works faster than P.