Ratio of milk and water in mixture A and mixture B is 3:2 and 5:4 respectively. Mixture A and mixture B are mixed to form mixture C. If quantity of milk is 95 liters more than quantity of water in mixture C and the ratio of total quantity of mixture A to that of mixture B is 14: 9, then find total quantity of water in mixture C.

Let mixture A have quantity 14k and mixture B have quantity 9k (ratio 14:9). In mixture A (milk:water = 3:2), milk = 3/5 × 14k = 8.4k, water = 2/5 × 14k = 5.6k. In mixture B (milk:water = 5:4), milk = 5/9 × 9k = 5k, water = 4/9 × 9k = 4k. In mixture C: total milk = 8.4k + 5k = 13.4k, total water = 5.6k + 4k = 9.6k. Given: milk - water = 95 liters. So: 13.4k - 9.6k = 95, giving 3.8k = 95, so k = 25. Water in mixture C = 9.6k = 9.6 × 25 = 240 liters. Option C is correct.