Multiple choice

In a certain mixture of two liquids A and B; the B concentration of the mixture is 20%. When 20 liter of the mixture is removed and then 9 liter of a mixture of A and B having 55% A concentration is added the B concentration of the resultant mixture becomes 35%. Find the difference in the quantity of the liquid A in the initial and the final mixture.

  1. 9.75

  2. 11.05

  3. 20.80

  4. 10

  5. 25
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let initial mixture be 100L (20L B, 80L A). After removing 20L: remaining is 64L A, 16L B. Adding 9L of 55% A means 4.95L A, 4.05L B added. Final mixture: 68.95L A, 20.05L B in 89L total. Difference in A = 68.95 - 64 = 4.95L. In 100L equivalent: (4.95/89) × 100 ≈ 11.05L. This matches option B.

Keep practicing — related questions