25 days of Mike's wages can be paid by a certain sum of money. The same amount of money is sufficient to pay Chester's wages for 20 days. Find the number of days for which the money will be sufficient to pay the wages of both if they work together?
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10 days
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11 days
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$\(\frac{100}{9}\) days$
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$\(\frac{110}{9}\) days$
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None of these
C
Correct answer
Explanation
Mike works 25 days on the money, Chester works 20 days on the same money. Total money = M. Mike's daily wage = M/25, Chester's daily wage = M/20. Working together, their combined daily wage = M/25 + M/20 = 9M/100. Days the money lasts = M / (9M/100) = 100/9 = 11 1/9 days. Option C (100/9 days) matches.