Multiple choice

The three vessels are X, Y and Z. The ratio of ingredients A and B in vessel X is 6: 5, the ratio of ingredients B and C in vessel Y is 7: 4 and the ratio of ingredients C and A in vessel Z is 3: 8 , the mixture of the three vessels is mixed in ratio of 2 : 5 : 8 and placed in a new vessel P, then what is the percentage of ingredient B in the new vessel ? (near to two decimal point )

  1. $37.27 %$
  2. $33.37 %$
  3. $23.23 %$
  4. $27.27 %$
  5. $None of the above$
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Vessel X (ratio A:B = 6:5) gives B as 5/11 of mixture. Vessel Y (ratio B:C = 7:4) gives B as 7/11. Vessel Z (ratio C:A = 3:8) gives B as 0. Using mixing ratio 2:5:8, total B = 2(5/11) + 5(7/11) + 8(0) = 45/11. Total volume = 2+5+8 = 15. Percentage of B = (45/11)/15 x 100 = 27.27%.

Keep practicing — related questions