From container A containing 54 liter of mixture of milk and water in ratio of 8 : 1 , 18 liter of the mixture is taken out and poured into container B in which ratio of milk to water is 3 : 1. If difference between total milk and total water in container B is 30 liter then find the quantity of initial mixture in container B.

Container A: 54L, milk:water = 8:1, so milk = 48L, water = 6L. 18L taken out (same ratio: 16L milk, 2L water). Added to container B (milk:water = 3:1). Let B initial have 3x milk, x water = 4x total. After adding: milk = 3x+16, water = x+2. Difference = (3x+16) - (x+2) = 2x+14 = 30. So 2x = 16, x = 8. Initial B = 4x = 32L. Answer C is correct.