Multiple choice

Calculate the probability of forming different words in which letters of word ABJURED can be arranged so that vowels always comes together.

  1. $1/6$
  2. $3/35$
  3. $1/9$
  4. $1/7$
  5. $5/7$
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Total arrangements of ABJURED (7 distinct letters) = 7! = 5040. Treat vowels (A, U, E) as one unit: we have 5 units to arrange in 5! = 120 ways. The 3 vowels can be arranged within their group in 3! = 6 ways. Total arrangements with vowels together = 120 × 6 = 720. Probability = 720/5040 = 1/7. Option D is correct.

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