Multiple choice

A man can reach a certain place in 21.75 hours. If he reduces his speed by (\frac{1}{15})th, he goes 10 km less in that time. Find the total distance covered by him.

  1. 140 km

  2. 150 km

  3. 142.5 km

  4. 160 km

  5. None of these
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let original speed = s km/h. Distance = s × 21.75. Reduced speed = (14/15)s, distance in same time = (14/15)s × 21.75. Difference = s × 21.75 - (14/15)s × 21.75 = s × 21.75 × (1/15) = 10 km. So s × 1.45 = 10, giving s = 50/7. Total distance = (50/7) × 21.75 = 50 × 3.09 = 154.5, which rounds to approximately 150 km.

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