Distance between two places A and B is 266 km, a train leaves from A to B and simultaneously another train leaves from B to A and meet at the end in 14 hours. If the former trains travels 3 km faster than the other, then speed of train from B is.

Distance = 266 km, trains meet after 14 hours. Let slower train speed (from B) = x km/h, then faster train speed (from A) = (x+3) km/h. Relative speed = x + (x+3) = 2x + 3 km/h. Distance covered when they meet = 266 km. Time = 266 / (2x + 3) = 14 hours. So 266 = 14(2x + 3). 266 = 28x + 42. 28x = 224. x = 8 km/h. Therefore, train from B travels at 8 km/h.