Two varieties of sugar are mixed together in a certain ratio. The cost of mixture per Kg is Rs 0.50 less than that of the superior and Rs. 0.75 more than the inferior variety. The ratio in which the superior and inferior varieties have been mixed is?

Use the allegation method for mixture problems. If mixture cost is M, superior cost is S, and inferior cost is I, then the ratio of S:I in the mixture is (M-I):(S-M). Here M is 0.50 less than S and 0.75 more than I. Set up: Let S = x, then M = x-0.50. Also M = y+0.75 where y is inferior cost. By allegation: (x-0.50-y):(x-(x-0.50)) = 3:2.