Rohit and Mohit start walking from A to B at the same time. After arriving at B, they immediately return to A and they first meet at a distance of 15 km from B. If the difference of their speed is 60 km / h, then find the speed of the faster person? If A and B are 60 km apart.

Distance AB = 60 km. They first meet 15 km from B, meaning the faster person covers 60 + 15 = 75 km while the slower covers 60 - 15 = 45 km in the same time. Their speed ratio is 75:45 = 5:3. Let speeds be 5x and 3x. Difference is 2x = 60, so x = 30. Faster speed = 5 × 30 = 150 km/h. This is a standard relative speed problem with return journey.