Given that the length of the paths of a ball thrown with different speeds by two boys are the same, if they take 0.6 seconds and 1 seconds respectively to cover the said length, what is the average speed of travel for the first throw, if the same for the second is 96 km/hr?

Distance = Speed × Time. Since distances are equal: S₁ × 0.6 = S₂ × 1. Given S₂ = 96 km/hr, S₁ × 0.6 = 96 × 1 = 96, so S₁ = 96/0.6 = 160 km/hr. Option A (100) incorrectly adds 40% to 96. Option B (150) uses 96 × 1.5625 incorrectly. Option D (200) mistakenly uses 96 × 2. This tests the inverse relationship between speed and time for constant distance.