A and B together can do a piece of work in 30 days. A having worked for 16 days, B finishes the remaining work in 44 days. In how many days shall B finish the work alone? A और B मिलकर किसी कार्य को 30 दिन में पूरा कर सकते हैं। A, 16 दिन कार्य करता हैं और शेष कार्य B, 44 दिन में पूरा करता हैं। B कार्य को अकेले कितने दिनों में पूरा करेगा?

A and B together do 1/30 of work per day. In 16 days, A does 16/A of work. Remaining work = 1 - 16/A. B completes this in 44 days at rate 1/B per day, so (1 - 16/A) = 44/B. Also 1/A + 1/B = 1/30. From the work equation: B(1 - 16/A) = 44, so B - 16B/A = 44. Since 1/A = 1/30 - 1/B, we get B - 16B(1/30 - 1/B) = 44, which gives B - 16B/30 + 16 = 44, so B(1 - 16/30) = 28, B(14/30) = 28, B = 28 × 30/14 = 60 days.