Multiple choice

If the radii of the ends of a bucket 24 cm. high are 5 cm. and 15 cm., the curved surface area of the bucket is -

  1. $520\pi cm^2$
  2. $676\pi cm^2$
  3. $480\pi cm^2$
  4. $576\pi cm^2$
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A Correct answer
Explanation

The bucket is a frustum of a cone with r=5 cm, R=15 cm, h=24 cm. Slant height l = sqrt(h^2 + (R-r)^2) = sqrt(24^2 + 10^2) = sqrt(576+100) = sqrt(676) = 26 cm. Curved surface area = pi * l * (R+r) = pi * 26 * (15+5) = 520pi cm^2.

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