Multiple choice

Two persons A and B start moving at each other from point P and Q respectively which are 1400 Km apart. Speed of A is 50 Km/hr and that of B is 20 Km/hr. How far is A from Q when he meets B for the 2nd time?

  1. 900

  2. 476.67

  3. 933.33

  4. 500

  5. None of these

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Speed ratio A:B = 50:20 = 5:2. Total distance = 1400 km. First meeting: A travels (5/7)×1400 = 1000 km. First return to Q: A travels another 1000 km to reach Q. Second meeting: A travels (5/7)×1400 = 1000 km from Q, so A's total from P = 1000 + 1000 + 1000 = 3000 km. Distance from Q = 3000 - 2×1400 = 200 km from P towards Q, which is 1400 - 200 = 1200 km from P, or 933.33 km from Q.