Multiple choice technology

What will be printed out if you attempt to compile and run the following code? int i=9; switch (i) { default: System.out.println("default"); case 0: System.out.println("zero"); break; case 1: System.out.println("one"); case 2: System.out.println("two"); }

  1. default

  2. default, zero

  3. error default clause not defined

  4. no output displayed
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

In switch statements without a matching case, execution falls through to the default case, then continues to subsequent cases unless break is encountered. Since i=9 matches no case, default executes (prints 'default'), then execution continues to case 0 (prints 'zero') where break stops it.

AI explanation

To answer this question, let's go through each option to understand why it is correct or incorrect:

Option A) default - This option is incorrect because the "default" case in a switch statement is only executed if none of the other cases match the value being switched on. In this case, the value of "i" is 9, so none of the cases match and the "default" case will be executed.

Option B) default, zero - This option is correct. Since none of the cases match the value of "i", the "default" case will be executed. However, there is no break statement after the "default" case, so the code will fall through to the next case. In this case, the next case is 0, so the code will execute the "zero" case as well. Therefore, both "default" and "zero" will be printed.

Option C) error default clause not defined - This option is incorrect. The "default" case is defined in the switch statement, so there is no error in the code.

Option D) no output displayed - This option is incorrect. The code will produce output because the "default" and "zero" cases will be executed.

The correct answer is B. The output will be "default, zero" because both the "default" and "zero" cases will be executed.

Keep practicing — related questions