A solution of sugar and water contains 16% of sugar by weight. If 64 kg of it is evaporated and the solution then contains 24% of Sugar what was the original quantity of solution?

Let the original quantity be x kg. Sugar initially = 0.16x. After evaporating 64 kg, remaining solution = x - 64 kg. New sugar percentage is 24%, so 0.16x = 0.24(x - 64). Solving: 0.16x = 0.24x - 15.36, which gives 0.08x = 15.36, so x = 15.36/0.08 = 192 kg. Since 1 kg of water ≈ 1 liter, the answer is approximately 192 liters. The key principle: the amount of sugar remains constant; only water evaporates.