Multiple choice

A, B and C can finish a work together in 12 days, if efficiency of A and C is twice of B while efficiency of A and B is thrice of C. find out the time taken by C alone?

  1. 24 days

  2. 48 days

  3. 36 days

  4. 12 days

  5. 60 days
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let efficiencies be A, B, C. Given A+C = 2B and A+B = 3C. From A = 2B - C, substituting: 2B - C + B = 3C, so 3B = 4C, B = 4C/3. Then A = 2(4C/3) - C = 5C/3. Combined efficiency A+B+C = 5C/3 + 4C/3 + C = 4C. Since they finish in 12 days, 4C × 12 = 1 work, so C = 1/48 work per day. C alone needs 48 days.

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