Multiple choice

In given question, two equations numbered I and II are given. You have to solve both the equations and give answer: I. (3p^2 – 10p + 3 = 0) II. (q^2 – 5q + 6 = 0)

  1. If p ≥ q

  2. If p > q

  3. If p ≤ q

  4. If p < q

  5. If p = q or relationship between p and q cannot be established
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

For 3p^2 - 10p + 3 = 0, factoring gives (3p-1)(p-3) = 0, so p = 1/3 or p = 3. For q^2 - 5q + 6 = 0, factoring gives (q-2)(q-3) = 0, so q = 2 or q = 3. The relationships vary: when p = 1/3, p < q (for both q values); when p = 3, p can equal q = 3 or be greater than q = 2. Since the relationship varies, it cannot be established.

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