Multiple choice

In each of these questions, two equations (a) and (b) are given. You have to solve both the equations and choose the correct option.(a) x^2 – 6x + 8 = 0 (b) y^2 – 8y + 15 = 0

  1. $x > y$
  2. $x ≤ y$
  3. $x ≥ y$
  4. $x < y$

  5. x = y or relationship between x and y can't be established
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Solving (a): x²-6x+8=0 gives (x-2)(x-4)=0, so x=2 or 4. Solving (b): y²-8y+15=0 gives (y-3)(y-5)=0, so y=3 or 5. Since x can be 2 or 4 and y can be 3 or 5, we have cases where xy (when x=4). No single relationship always holds.

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