Multiple choice

In each of the following questions, two equations are I and II given. You have to solve them and give answer I. $(2x^2 - 17x + 36 = 0)$ II. $(7y^2 - 29y + 30 = 0)$

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or relationship cannot be established
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Solve equation I: 2x² - 17x + 36 = 0 factors to (2x - 9)(x - 4) = 0, giving x = 4.5 or x = 4. Solve equation II: 7y² - 29y + 30 = 0 factors to (7y - 14)(y - 2.14...) ≈ y = 2 or y = 2.14. Both x values (4, 4.5) are greater than both y values (2, 2.14), so x > y is correct.

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