Multiple choice

In each of the following question, two equations are I and II given. You have to solve them and give answer $I. (5x^2 + 3x = 14)\nII. (5y^2 + 11y = 36)$

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or relationship cannot be established
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Solving equation I: 5x² + 3x - 14 = 0 factors as (5x - 7)(x + 2) = 0, so x = 7/5 = 1.4 or x = -2. Solving equation II: 5y² + 11y - 36 = 0 factors as (5y - 9)(y + 4) = 0, so y = 9/5 = 1.8 or y = -4. When x = 1.4, y = 1.8 gives x < y, but when x = -2, y = -4 gives x > y. Since the relationship changes based on which roots we compare, the relationship cannot be established.

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