Multiple choice

Akash when going slower by 15 Km/hr, reaches late by 45 hours. If he goes faster by 10 Km/hr from his original speed, he reaches early by 20 hours than the original time. Find the distance he covers.

  1. 8750 km

  2. 9750 km

  3. 1000 km

  4. 3750 km

  5. None of these
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Let original speed = v km/hr and original time = t hours. Distance d = vt. When v-15, time = t+45: d = (v-15)(t+45). When v+10, time = t-20: d = (v+10)(t-20). Equating and solving: vt = vt + 45v - 15t - 675 and vt = vt - 20v + 10t - 200. This gives v = 30 km/hr and t = 325 hours. Distance = 30 × 325 = 9750 km.

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