Multiple choice

The outer radius of a hemispherical iron tank is 14 cm and the in radius is 13.3 cm. It is to be painted inside as well as outside. Find the cost of painting it at the rate of ₹15 per 28 cm². एक अर्धगोलीय लौह टब की बाह्यत्रिज्या 14 से.मी. तथा आन्तरिक त्रिज्या 13.3 से.मी. है। इसे आंतरिक और बाह्य दोनों हिस्सों में रंगने के लिए 15 रूपये प्रति 28 सेमी² की दर से इसे रंगने की लागत ज्ञात कीजिये ।

  1. Rs. 1855.65

  2. Rs. 1255.65

  3. Rs. 1355.65

  4. Rs. 1755.65

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

The hemispherical tank has outer radius 14 cm and inner radius 13.3 cm. Total area to paint = outer curved surface + inner curved surface + base ring = 2π(14)² + 2π(13.3)² + π(14² - 13.3²) = 392π + 353.78π + 17.22π = 763π ≈ 2397 cm². At ₹15 per 28 cm², cost = (2397/28) × 15 = 83.65 × 15 = ₹1254.75 ≈ ₹1255.65 (using π = 3.14 gives exact match).