The base is quadrilateral ABCD with AB = 9 cm, BC = 14 cm, CD = 13 cm, DA = 12 cm, and ∠DAB = 90°. Drawing diagonal BD, we get two right triangles ABD and BCD. In ΔABD: AB² + AD² = BD², so BD² = 9² + 12² = 81 + 144 = 225, hence BD = 15 cm. Area of quadrilateral ABCD = Area of ΔABD + Area of ΔBCD. Area of ΔABD = 1/2 × 9 × 12 = 54 cm². For ΔBCD, using Heron's formula or recognizing it as a 5-12-13 triangle (scaled), the area is 1/2 × 5 × 12 = 30 cm² (where 5 and 12 are the legs if we drop an altitude). Actually, let me recalculate: with sides 13, 14, 15, the area can be found using Heron's formula. Semi-perimeter = (13+14+15)/2 = 21. Area = √(21×8×7×6) = √7056 = 84 cm². Total area = 54 + 84 = 138 cm². Volume of prism = Base area × height = 2070, so height = 2070/138 = 15 cm. Perimeter of base = 9 + 14 + 13 + 12 = 48 cm. Lateral surface area = Perimeter × height = 48 × 15 = 720 cm².