Multiple choice

In each of these questions, two equations (a) and (b) are given. You have to solve both the equations and choose the correct option. a) (x^2 - 32x + 247 = 0) b) (3y^2 + 13y + 12 = 0)

  1. x > y

  2. x ≤ y

  3. x ≥ y

  4. x < y

  5. x = y or relationship between x and y can't be established

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Solving equation (a): x^2-32x+247=0 gives x=(32±√(1024-988))/2=(32±√36)/2=(32±6)/2, so x=19 or x=13. Solving equation (b): 3y^2+13y+12=0 gives y=(-13±√(169-144))/6=(-13±5)/6, so y=-4/3 or y=-3. Since x values (13, 19) are always greater than y values (-4/3, -3), x > y is always true. Option A is correct.