Multiple choice

In each of these questions, two equations (a) and (b) are given. You have to solve both the equations and choose the correct option.( (a) x^2 – 50x +589 =0 ) ( (b) y^2 -19y -416 =0 )

  1. x > y

  2. x ≤ y

  3. x ≥ y

  4. x < y

  5. x = y or relationship between x and y can't be established
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

For x² - 50x + 589 = 0, factors are (x-31)(x-19) = 0, giving x = 31 or x = 19. For y² - 19y - 416 = 0, factors are (y-32)(y+13) = 0, giving y = 32 or y = -13. When x = 31 and y = 32, we have x < y, but when x = 31 and y = -13, we have x > y. Since no single relationship holds consistently, the answer is that the relationship cannot be established.

Keep practicing — related questions