Multiple choice

In the following questions two equations I and II are given. You have to solve both the equations and give answer. $( (I) \ 12x^2 + 41x + 35 = 0 )( (II) \ 6y^2 + 31y + 28 = 0 )$

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or the relationship cannot be determined
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Solving the first equation gives x = -1.67 or x = -1.75. Solving the second equation gives y = -1.17 or y = -4. When comparing values: x = -1.67 is between y values (-1.17 > x > -4). This means sometimes x > y and sometimes x < y, making the relationship undetermined.

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