Multiple choice

In each question two equations numbered I and II are given, you have to solve both the equations and choose the correct answer. $I. (x^2 + x - 20 = 0)$ $II. (2y^2 + 13y + 15 = 0)$

  1. $\(x > y\)$
  2. $\(x < y\)$
  3. $\(x \le y\)$
  4. $\(x \ge y\)$

  5. x = y or the relationship cannot be established
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Solving equation I: x² + x - 20 = 0 gives (x + 5)(x - 4) = 0, so x = -5 or x = 4. Solving equation II: 2y² + 13y + 15 = 0 gives (2y + 3)(y + 5) = 0, so y = -3/2 or y = -5. Comparing values: x = -5 = y = -5, x = 4 > y = -3/2, x = 4 > y = -5. Since x is sometimes equal to y and sometimes greater than y, the exact relationship cannot be established.

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