Five workers P, Q, R, S, T are assigned to complete a work. P alone can complete the work in half time as compared to Q while R takes 7/4 time as compare to T and S’s efficiency is triple than Q while T takes 33% more time than P. R alone takes 28 days to complete the work. Total wages for the work is Rs 67200. If P and S left the work after first day and T left the work after fourth day then how much wages R will get for the remaining work?

R takes 28 days alone, so R's 1-day work = 1/28. Given relationships: T takes 33% more time than P means T takes 1.33P time. R takes 7/4 of T's time. P takes half time of Q. S is 3x efficient as Q. Solving: P takes 21 days, T takes 28 days, Q takes 42 days, S takes 14 days. Work done in Day 1 by all 5: 1/21 + 1/42 + 1/28 + 1/14 + 1/28 = 0.2381. Remaining work = 0.7619. R works alone for remaining days at rate 1/28. R's wage = Rs 67200 × 0.7619 × (1/28) × 28 = Rs 7200. Option C is correct.