Multiple choice

In each question two equations numbered I and II are given, you have to solve both the equation and choose the correct answer. $I. (3x^2 - 5x - 28 = 0) II. (2y^2 - 17y + 36 = 0)$

  1. X > Y

  2. X < Y

  3. X ≤ Y

  4. X ≥ Y

  5. X = Y or the relationship can’t be established
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Equation I: 3x² - 5x - 28 = 0. Solving: x = [5 ± √(25 + 336)]/6 = [5 ± √361]/6 = [5 ± 19]/6. So x = 24/6 = 4 or x = -14/6 = -7/3. Equation II: 2y² - 17y + 36 = 0. Solving: y = [17 ± √(289 - 288)]/4 = [17 ± √1]/4 = [17 ± 1]/4. So y = 18/4 = 4.5 or y = 16/4 = 4. Comparing: When x=4, y=4.5 gives x

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