Multiple choice

In each question two equations numbered I and II are given, you have to solve both the equation and choose the correct answer. $I. (3x^2 + 7x - 6 = 0)$ $II. (6(2y^2 + 1) = 17y)$

  1. X > Y

  2. X < Y

  3. X ≤ Y

  4. X ≥ Y

  5. X = Y or the relationship can’t be established

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Solve equation I: 3x² + 7x - 6 = 0 gives x = 2/3 or x = -3. Solve equation II: 12y² - 17y + 6 = 0 gives y = 3/4 or y = 2/3. Comparing all value pairs: -3 < 3/4, -3 < 2/3, 2/3 = 2/3, and 2/3 < 3/4. Therefore x ≤ y is always true.