Multiple choice

If the height, curved surface area and the volume of a cone are h, c and v respectively then- 3πvh3–c2h2+9v2 will be equal to- यदि एक शंकु की ऊँचाई, वक्रपृष्ठ क्षेत्रफल और आयतन h,c और v है तो 3πvh3–c2h2+9v2 बराबर होगा-

  1. –1

  2. 9V

  3. 1

  4. 0
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D Correct answer
Explanation

For a cone, the expression 3πv-h² + 9v² - c²h² simplifies to 0 by substituting v = (1/3)πr²h and c = πrl, then using l² = r² + h². After algebraic manipulation, all terms cancel out, yielding 0. This tests the relationship between cone dimensions.

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