Multiple choice

In each of the following question, two equations (I) and (II) are given. You have to solve them and answer the question.\newline I. (x^2 + 9x + 14 = 0)\newline II. (y^2 + y - 2 = 0)

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or relationship cannot be established
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Solve both quadratic equations: x^2 + 9x + 14 = 0 factors to (x+2)(x+7) = 0, giving x = -2 or x = -7. For y^2 + y - 2 = 0, factoring gives (y+2)(y-1) = 0, so y = -2 or y = 1. Comparing all values: x values are -2 and -7, y values are -2 and 1. In all cases x ≤ y (equality occurs when both are -2).

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