In each of the following questions, two equations are given. You have to solve them and Give answer. ( (I) ) (34x^2 - 9x - 385 = 0 ) ( (II) ) ( 31y^2 - 150y + 171 = 0 )

For equation (I): 34x² - 9x - 385 = 0. Using the quadratic formula: x = [9 ± √(81 - 4×34×(-385))]/(2×34) = [9 ± √(81 + 52360)]/68 = [9 ± √52441]/68 = [9 ± 229]/68, giving x = 238/68 = 3.5 or x = -220/68 = -3.24. For equation (II): 31y² - 150y + 171 = 0. Using the quadratic formula: y = [150 ± √(22500 - 4×31×171)]/(2×31) = [150 ± √(22500 - 21204)]/62 = [150 ± √1296]/62 = [150 ± 36]/62, giving y = 186/62 = 3 or y = 114/62 = 1.84. Comparing: x = 3.5 > y = 3, but x = -3.24 < y = 1.84. Since the relationship between x and y is not consistent (one value of x is greater while the other is smaller), the relationship cannot be established.