In each of the following questions, two equations are given. You have to solve them and Give answer. (I) (55x^2 + 309x = -378) (II) (26y^2 - 251y = 231)

For equation (I): 55x² + 309x = -378 becomes 55x² + 309x + 378 = 0. Using the quadratic formula, x = [-309 ± √(309² - 4×55×378)]/(2×55) = [-309 ± √12321]/110 = [-309 ± 111]/110, giving x = -1.8 or x = -3.82. For equation (II): 26y² - 251y = 231 becomes 26y² - 251y - 231 = 0. Using the quadratic formula, y = [251 ± √(251² - 4×26×(-231))]/(2×26) = [251 ± √87025]/52 = [251 ± 295]/52, giving y = 10.5 or y = -0.846. Comparing the values: both x values (-1.8, -3.82) are less than both y values (-0.846, 10.5). Therefore, x < y.