Multiple choice

In each question two equations numbered I and II are given, you have to solve both the equation and state the correct relationship. (I. ) (x^2 - 5x - 24 = 0 ) (II. ) (2y^2 + 19y + 35 = 0)

  1. $\(X > Y\)$
  2. $\(X < Y\)$
  3. $\(X ≤ Y\)$
  4. $\(X ≥ Y\)$

  5. X = Y or the relationship cannot be established
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

Solve equation I: x² - 5x - 24 = 0 gives x = 8, -3. Solve equation II: 2y² + 19y + 35 = 0 gives y = -5, -3.5. Since x has both positive and negative values while y is always negative, and specifically -3 > -3.5 but 8 > -5, the relationship cannot be consistently established.

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