Multiple choice

In each of the following question, two equations are I and II given. You have to solve them and give answer. I. (6x^2 + x – 1 = 0) II. (8y^2 + 10y + 3 = 0)

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or relationship cannot be established

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Solving equation I: 6x^2 + x - 1 = 0 factors to (3x - 1)(2x + 1) = 0, giving x = 1/3 or x = -1/2. Solving equation II: 8y^2 + 10y + 3 = 0 factors to (4y + 3)(2y + 1) = 0, giving y = -3/4 or y = -1/2. When y = -1/2, x can be -1/2 (x = y) or x = 1/3 (x > y). Therefore, x ≥ y.