Multiple choice

In each of the following question, two equations are I and II given. You have to solve them and give answer I. (x^2 - x - 12 = 0) II. (y^2 + 9y + 20 = 0)

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or relationship cannot be established
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Solving equation I: x^2 - x - 12 = 0 gives x = 4 or x = -3. Solving equation II: y^2 + 9y + 20 = 0 gives y = -4 or y = -5. Comparing all possible pairs: when x = 4, x > y (both y values are negative); when x = -3, x > -4 but x > -5. In all cases, x > y.

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