Multiple choice

In each of the following question, two equations (I) and (II) are given. You have to solve them and find the correct relationship- I. (p^2 - 12p + 32 = 0) II. (q^2 - 7q + 12 = 0)

  1. If p > q

  2. If p ≤ q

  3. If p ≥ q

  4. If p < q

  5. If p = q or relationship cannot be established
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Solving p² - 12p + 32 = 0 gives (p-4)(p-8) = 0, so p = 4 or 8. Solving q² - 7q + 12 = 0 gives (q-3)(q-4) = 0, so q = 3 or 4. Checking all pairs: when p=4, q can be 3 or 4 (p≥q); when p=8, q can be 3 or 4 (p>q). In all cases, p is always greater than or equal to q.

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