The side of the first square exceeds the side of another square by 4 cm. and the sum of the areas of the two squares is 400 sq. cm. Find the dimensions of the squares. पहले वर्ग की भुजा दूसरे वर्ग की भुजा से 4 सेमी. अधिक है, और इनके क्षेत्रफलों का योग 400 वर्ग सेमी. है | वर्गों की विमायें ज्ञात कीजिये |

Let the smaller side be x cm. Then x² + (x+4)² = 400. Expanding: x² + x² + 8x + 16 = 400, so 2x² + 8x - 384 = 0. Dividing by 2: x² + 4x - 192 = 0. Using the quadratic formula: x = [-4 ± √(16 + 768)]/2 = [-4 ± √784]/2 = [-4 ± 28]/2. Taking the positive value: x = 12 cm. The other square has side x+4 = 16 cm. These satisfy the conditions: 12² + 16² = 144 + 256 = 400.