Multiple choice

In each of the following questions, two equations are given, you have to solve them and- $I. (x^2 - 4 = 0)$ $II. (y^2 + 6y + 9 = 0)$

  1. $\(x < y\)$
  2. $\(x > y\)$
  3. $\(x \ge y\)$
  4. $\(x \le y\)$

  5. x = y or relationship cannot be established.
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

Solve each equation: From I, x²-4=0 gives x=±2. From II, y²+6y+9=0 factors as (y+3)²=0, so y=-3. Comparing all values: when x=2, x>-3; when x=-2, x>-3. In all cases x is greater than y.

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