In these questions, two equations numbered I and II are given. You have to solve both the equations and mark the appropriate option. I. (8x^2 + 25x + 3 = 0) II. (2y^2 + 17y + 30 = 0)

Solve equation I: 8x² + 25x + 3 = 0 factors to (8x+1)(x+3) = 0, so x = -1/8 = -0.125 or x = -3. Solve equation II: 2y² + 17y + 30 = 0 factors to (2y+5)(y+6) = 0, so y = -5/2 = -2.5 or y = -6. Comparing values: When x = -0.125, it's greater than both y values (-2.5, -6). When x = -3, it's greater than y = -6 but less than y = -2.5. Since the relationship varies (x > y in some cases, x < y in others), the relationship cannot be established.