Multiple choice

In the following questions two equations numbered I and II are given. You have to solve both the equations and Give answer:\ I. (3x^2 + 7x = 6)\ II. (6(2y^2 + 1) = 17y)

  1. If x > y

  2. If x < y

  3. If x ≥ y

  4. If x ≤ y

  5. If x = y or relation cannot be established.
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Equation I: 3x² + 7x - 6 = 0 factors to (3x-2)(x+3) = 0, so x = 2/3 or x = -3. Equation II: 6(2y²+1) = 17y becomes 12y² - 17y + 6 = 0, giving y = 3/4 or y = 2/3. Comparing: 2/3 = 2/3, -3 < 3/4, -3 < 2/3. Thus x ≤ y in all cases. Option D is correct.

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