Multiple choice

In each of the following question, two equations (I) and (II) are given. You have to solve them and answer the question.\newline I. (15x^2 + 68x + 77 = 0)\newline II. (3y^2 + 29y + 68 = 0)

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or relationship cannot be established
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Solving equation I: 15x² + 68x + 77 = 0 factors as (5x + 11)(3x + 7) = 0, giving x = -11/5 = -2.2 or x = -7/3 ≈ -2.33. Solving equation II: 3y² + 29y + 68 = 0 factors as (3y + 17)(y + 4) = 0, giving y = -17/3 ≈ -5.67 or y = -4. Comparing the values: x (-2.2 or -2.33) > y (-5.67 or -4), so x > y is correct. Answer A is correct.

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