Multiple choice

In each of the following question, two equations (I) and (II) are given. You have to solve them and answer the question.\ (I.) (4x^2 - 7x + 3 = 0)\ (II.) (y^2 - 2y + 1 = 0)

  1. If x > y

  2. If x ≥ y

  3. If x < y

  4. If x ≤ y

  5. If x = y or relationship cannot be established
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

Solving equation I: 4x² - 7x + 3 = 0 factors to (4x-3)(x-1)=0, giving x=3/4=0.75 or x=1. Solving equation II: y² - 2y + 1 = 0 is (y-1)²=0, giving y=1 (repeated root). Comparing: when x=0.75, x

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