Multiple choice

In each of the following questions, two equations I and II have been given. Solve these questions and answer I. (x^{2} + 12x + 36 = 0) II. (y^{2} = 16)

  1. If x < y

  2. If x ≤ y

  3. If x = y or the relation cannot be established

  4. If x ≥ y

  5. If x > y
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A Correct answer
Explanation

Equation I: x² + 12x + 36 = 0 is (x+6)² = 0, so x = -6 (repeated root). Equation II: y² = 16 gives y = 4 or y = -4. Comparing: if y = 4, then -6 < 4 is true. If y = -4, then -6 < -4 is also true. In both cases, x < y, so x is strictly less than y.

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