Multiple choice

In each of the following questions, two equations I and II have been given. Solve these questions and answer I. 9x2 + 3x – 2 = 0 II. 8y2 + 6y + 1 = 0

  1. If x < y

  2. If x ≤ y

  3. If x = y or the relation cannot be established

  4. If x ≥ y

  5. If x > y
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Equation I: 9x² + 3x - 2 = 0 gives x = 1/3 ≈ 0.33 or x = -2/3 ≈ -0.67. Equation II: 8y² + 6y + 1 = 0 gives y = -1/4 = -0.25 or y = -1/2 = -0.5. When x = 0.33, x > both y values. When x = -0.67, x < both y values. Since x can be greater than OR less than y depending on which roots you compare, the relationship cannot be established.

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